The problem asks for the magnitude and direction of the net force acting on the car. There are four forces acting on the car: 2500 N downwards, 2500 N upwards, 50 N to the left, and 20 N to the right.

Applied MathematicsPhysicsForcesNet ForceVector Addition
2025/3/31

1. Problem Description

The problem asks for the magnitude and direction of the net force acting on the car. There are four forces acting on the car: 2500 N downwards, 2500 N upwards, 50 N to the left, and 20 N to the right.

2. Solution Steps

First, consider the vertical forces.
The force upwards is 2500 N and the force downwards is 2500 N.
The net vertical force is 2500 N2500 N=0 N2500 \ N - 2500 \ N = 0 \ N.
Next, consider the horizontal forces.
The force to the left is 50 N and the force to the right is 20 N.
The net horizontal force is 50 N20 N=30 N50 \ N - 20 \ N = 30 \ N to the left.
Therefore, the net force on the car is 30 N to the left.

3. Final Answer

D. 30 N to the left

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