Question 33: Yakubu's scores in five out of six subjects are 95, 87, 85, 93, and 94. If he requires an average score of 90 to get promoted, what must be the minimum score in the sixth subject? Question 34: A right pyramid has a square base of side 10 cm. If the volume is 700 $cm^3$, find the height. Question 35: The bearing of F from G is 064°. What is the bearing of G from F?

Applied MathematicsAveragesVolume of a PyramidBearingsGeometryWord Problems
2025/6/3

1. Problem Description

Question 33: Yakubu's scores in five out of six subjects are 95, 87, 85, 93, and
9

4. If he requires an average score of 90 to get promoted, what must be the minimum score in the sixth subject?

Question 34: A right pyramid has a square base of side 10 cm. If the volume is 700 cm3cm^3, find the height.
Question 35: The bearing of F from G is 064°. What is the bearing of G from F?

2. Solution Steps

Question 33:
Let xx be the score in the sixth subject.
The average score of the six subjects is given by
95+87+85+93+94+x6\frac{95+87+85+93+94+x}{6}.
We want this average to be at least
9

0. So, we have the inequality:

95+87+85+93+94+x690\frac{95+87+85+93+94+x}{6} \ge 90.
95+87+85+93+94+x90×695+87+85+93+94+x \ge 90 \times 6.
454+x540454+x \ge 540.
x540454x \ge 540 - 454.
x86x \ge 86.
Therefore, the minimum score in the sixth subject is
8
6.
Question 34:
The volume of a pyramid is given by the formula
V=13×base_area×heightV = \frac{1}{3} \times base\_area \times height.
The base is a square with side 10 cm. So, the base area is 10×10=10010 \times 10 = 100 cm2cm^2.
The volume is given as 700 cm3cm^3.
Let hh be the height. Then,
700=13×100×h700 = \frac{1}{3} \times 100 \times h.
700=100h3700 = \frac{100h}{3}.
2100=100h2100 = 100h.
h=2100100h = \frac{2100}{100}.
h=21h = 21 cm.
Therefore, the height of the pyramid is 21 cm.
Question 35:
The bearing of F from G is 064°. This means that if you are standing at G and facing North, you need to rotate 64° clockwise to face F.
The bearing of G from F is the angle measured clockwise from North at F to G.
The difference between the bearings is 180°. Since 064° is less than 180°, we add 180° to 064°.
Bearing of G from F = 064° + 180° = 244°.
Therefore, the bearing of G from F is 244°.

3. Final Answer

Question 33: A. 86
Question 34: B. 21 cm
Question 35: C. 244°

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