Laila rides a bicycle. After 9 hours, she is 20 miles from her house. After 12 hours, she is 26 miles from her house. We need to find her average rate during the last 3 hours of her trip.

1. Problem Description

Laila rides a bicycle. After 9 hours, she is 20 miles from her house. After 12 hours, she is 26 miles from her house. We need to find her average rate during the last 3 hours of her trip.

2. Solution Steps

The last 3 hours of her trip are between hour 9 and hour

1

2. At hour 9, she is 20 miles away.

At hour 12, she is 26 miles away.

The change in distance is $26 - 20 = 6$ miles.

The change in time is $12 - 9 = 3$ hours.

The average rate is the change in distance divided by the change in time.

$Average\, rate = \frac{Change\, in\, distance}{Change\, in\, time}$

$Average\, rate = \frac{6\, miles}{3\, hours} = 2\, miles\, per\, hour$

3. Final Answer

2 miles per hour