The sum of two numbers $p$ and $m$ is 12, and $p^3 + m^3 = 360$. We need to find the value of $pm$.

AlgebraAlgebraic EquationsPolynomialsFactoringProblem Solving
2025/7/4

1. Problem Description

The sum of two numbers pp and mm is 12, and p3+m3=360p^3 + m^3 = 360. We need to find the value of pmpm.

2. Solution Steps

We are given that
p+m=12p + m = 12 (1)
p3+m3=360p^3 + m^3 = 360 (2)
We know that:
p3+m3=(p+m)(p2pm+m2)p^3 + m^3 = (p + m)(p^2 - pm + m^2)
p3+m3=(p+m)((p+m)23pm)p^3 + m^3 = (p + m)((p + m)^2 - 3pm)
Substitute the given values into the equation:
360=12((12)23pm)360 = 12((12)^2 - 3pm)
360=12(1443pm)360 = 12(144 - 3pm)
Divide both sides by 12:
30=1443pm30 = 144 - 3pm
Rearrange the equation to solve for pmpm:
3pm=144303pm = 144 - 30
3pm=1143pm = 114
Divide by 3:
pm=1143pm = \frac{114}{3}
pm=38pm = 38

3. Final Answer

The value of pmpm is 38.

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