The problem states that four numbers are in the ratio 11:19:5:7. The sum of these four numbers is 2289. We need to find the sum of the first and the third number.

AlgebraRatio and ProportionLinear EquationsWord Problem
2025/7/4

1. Problem Description

The problem states that four numbers are in the ratio 11:19:5:

7. The sum of these four numbers is

2
2
8

9. We need to find the sum of the first and the third number.

2. Solution Steps

Let the four numbers be 11x11x, 19x19x, 5x5x, and 7x7x.
Their sum is given as
2
2
8

9. Therefore,

11x+19x+5x+7x=228911x + 19x + 5x + 7x = 2289
42x=228942x = 2289
x=228942=76314=54.5x = \frac{2289}{42} = \frac{763}{14} = 54.5
We need to find the sum of the first and third numbers, which is 11x+5x=16x11x + 5x = 16x.
16x=16×228942=16×76314=8×7637=61047=87216x = 16 \times \frac{2289}{42} = 16 \times \frac{763}{14} = 8 \times \frac{763}{7} = \frac{6104}{7} = 872

3. Final Answer

The sum of the first and third numbers is 872.

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