The problem asks us to find the pressure exerted by a cylinder on the floor. We are given the volume of the cylinder ($1200 cm^3$), the height of the cylinder ($40 cm$), and the force exerted by the cylinder on the floor ($90 N$). We are also given the formula for pressure: $pressure = \frac{force}{area}$.

1. Problem Description

The problem asks us to find the pressure exerted by a cylinder on the floor. We are given the volume of the cylinder ($1200 cm^3$), the height of the cylinder ($40 cm$), and the force exerted by the cylinder on the floor ($90 N$). We are also given the formula for pressure: $pressure = \frac{force}{area}$.

2. Solution Steps

First, we need to find the area of the base of the cylinder.

We know that the volume of a cylinder is given by:

$Volume = Area \times Height$

So, $Area = \frac{Volume}{Height}$

Plugging in the given values, we have:

$Area = \frac{1200 cm^3}{40 cm} = 30 cm^2$

Now we need to convert the area from $cm^2$ to $m^2$ because the force is given in Newtons, which is equivalent to $kg \cdot m/s^2$, which uses meters.

$1 m = 100 cm$, so $1 m^2 = (100 cm)^2 = 10000 cm^2$

Therefore, $30 cm^2 = \frac{30}{10000} m^2 = 0.003 m^2$

Now we can use the formula for pressure:

$Pressure = \frac{Force}{Area}$

We are given the force as $90 N$, and we calculated the area as $0.003 m^2$.

$Pressure = \frac{90 N}{0.003 m^2} = 30000 N/m^2$

3. Final Answer

The pressure is $30000 N/m^2$.