We are given a right triangle FGH with right angle at G. We are given the length of the hypotenuse FH as 98 and the length of the side GH as 56. We need to find the measure of angle F, which is labeled as $x^{\circ}$, and round to the nearest tenth of a degree.

1. Problem Description

We are given a right triangle FGH with right angle at G. We are given the length of the hypotenuse FH as 98 and the length of the side GH as

5

6. We need to find the measure of angle F, which is labeled as $x^{\circ}$, and round to the nearest tenth of a degree.

2. Solution Steps

Since we are given the side opposite to angle F (GH) and the hypotenuse (FH), we can use the sine function to find the angle F.

$sin(x) = \frac{opposite}{hypotenuse}$

$sin(x) = \frac{GH}{FH}$

$sin(x) = \frac{56}{98}$

To find the value of $x$, we need to take the inverse sine (arcsin) of $\frac{56}{98}$.

$x = arcsin(\frac{56}{98})$

Using a calculator, we find:

$x = arcsin(\frac{56}{98}) \approx 34.84990167$ degrees

Rounding to the nearest tenth of a degree, we get:

$x \approx 34.8$ degrees

3. Final Answer

34.8 degrees