Alif deposited RM2500 in Bank Delima at the beginning of 2019 with an annual interest rate of 4%. We need to calculate the maturity value Alif receives at the end of 2024 if the interest is compounded (a) annually and (b) every 3 months.

Applied MathematicsCompound InterestFinancial MathematicsExponents
2025/7/10

1. Problem Description

Alif deposited RM2500 in Bank Delima at the beginning of 2019 with an annual interest rate of 4%. We need to calculate the maturity value Alif receives at the end of 2024 if the interest is compounded (a) annually and (b) every 3 months.

2. Solution Steps

(a) Compounded annually:
The formula for compound interest is:
A=P(1+r/n)ntA = P (1 + r/n)^{nt}
where:
A = the future value of the investment/loan, including interest
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (as a decimal)
n = the number of times that interest is compounded per year
t = the number of years the money is invested or borrowed for
In this case:
P=2500P = 2500
r=0.04r = 0.04
n=1n = 1
t=20242019=5t = 2024 - 2019 = 5
A=2500(1+0.04/1)(15)A = 2500 (1 + 0.04/1)^{(1*5)}
A=2500(1+0.04)5A = 2500 (1 + 0.04)^{5}
A=2500(1.04)5A = 2500 (1.04)^{5}
A=25001.2166529024A = 2500 * 1.2166529024
A=3041.632256A = 3041.632256
A3041.63A \approx 3041.63
(b) Compounded every 3 months:
In this case:
P=2500P = 2500
r=0.04r = 0.04
n=12/3=4n = 12/3 = 4
t=20242019=5t = 2024 - 2019 = 5
A=P(1+r/n)ntA = P (1 + r/n)^{nt}
A=2500(1+0.04/4)(45)A = 2500 (1 + 0.04/4)^{(4*5)}
A=2500(1+0.01)20A = 2500 (1 + 0.01)^{20}
A=2500(1.01)20A = 2500 (1.01)^{20}
A=25001.22019004A = 2500 * 1.22019004
A=3050.4751A = 3050.4751
A3050.48A \approx 3050.48

3. Final Answer

(a) If the interest is compounded annually, Alif will receive RM3041.63 at the end of
2
0
2

4. (b) If the interest is compounded every 3 months, Alif will receive RM3050.48 at the end of

2
0
2

4. The more frequently the interest is compounded, the higher the maturity value.

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