We are given a system of two linear equations: $y = x - 3$ $y = -4x - 8$ We need to find the values of $x$ and $y$ that satisfy both equations.

1. Problem Description

We are given a system of two linear equations:

$y = x - 3$

$y = -4x - 8$

We need to find the values of $x$ and $y$ that satisfy both equations.

2. Solution Steps

Since both equations are already solved for $y$, we can set them equal to each other:

$x - 3 = -4x - 8$

Now, we can solve for $x$:

Add $4x$ to both sides:

$x + 4x - 3 = -4x + 4x - 8$

$5x - 3 = -8$

Add 3 to both sides:

$5x - 3 + 3 = -8 + 3$

$5x = -5$

Divide both sides by 5:

$\frac{5x}{5} = \frac{-5}{5}$

$x = -1$

Now that we have the value of $x$, we can substitute it into either of the original equations to solve for $y$. Let's use the first equation:

$y = x - 3$

$y = -1 - 3$

$y = -4$

So the solution is $x = -1$ and $y = -4$.

3. Final Answer

$x = -1, y = -4$