The problem provides a table of $x$ and $y$ values for points on a linear graph. The goal is to find the gradient (slope) of the line.

AlgebraLinear EquationsSlopeCoordinate Geometry
2025/4/10

1. Problem Description

The problem provides a table of xx and yy values for points on a linear graph. The goal is to find the gradient (slope) of the line.

2. Solution Steps

The gradient (slope) of a line is given by the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are two points on the line.
We can choose any two points from the table. Let's use the first two points:
(x1,y1)=(6.20,3.90)(x_1, y_1) = (6.20, 3.90)
(x2,y2)=(6.85,5.20)(x_2, y_2) = (6.85, 5.20)
Now, we can plug these values into the formula:
m=5.203.906.856.20=1.300.65=2m = \frac{5.20 - 3.90}{6.85 - 6.20} = \frac{1.30}{0.65} = 2

3. Final Answer

The gradient (slope) of the line is

2. The answer is B.

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