We are asked to solve the following system of equations using the elimination method: $ -5x + 2y = -15 $ $ x - 2y = 3 $

AlgebraSystems of EquationsLinear EquationsElimination Method
2025/4/2

1. Problem Description

We are asked to solve the following system of equations using the elimination method:
5x+2y=15 -5x + 2y = -15
x2y=3 x - 2y = 3

2. Solution Steps

We can solve the system of equations by elimination. We observe that the yy terms have opposite signs in the two equations. Thus, we can directly add the two equations to eliminate yy.
(5x+2y)+(x2y)=15+3(-5x + 2y) + (x - 2y) = -15 + 3
5x+x+2y2y=12-5x + x + 2y - 2y = -12
4x=12-4x = -12
Dividing both sides by 4-4, we get
x=124x = \frac{-12}{-4}
x=3x = 3
Now, we substitute the value of xx into the second equation to find the value of yy:
x2y=3x - 2y = 3
32y=33 - 2y = 3
2y=33-2y = 3 - 3
2y=0-2y = 0
y=02y = \frac{0}{-2}
y=0y = 0
Thus, the solution to the system of equations is x=3x = 3 and y=0y = 0.

3. Final Answer

The solution is x=3x = 3 and y=0y = 0.
The solution as an ordered pair is (3,0)(3, 0).

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