The problem requires us to simplify the expression $-3a^2b(2ab^2 - 2b)$. This involves distributing $-3a^2b$ to both terms inside the parentheses.

AlgebraSimplificationExpressionsPolynomialsDistribution
2025/3/10

1. Problem Description

The problem requires us to simplify the expression 3a2b(2ab22b)-3a^2b(2ab^2 - 2b). This involves distributing 3a2b-3a^2b to both terms inside the parentheses.

2. Solution Steps

First, distribute 3a2b-3a^2b to 2ab22ab^2:
(3a2b)(2ab2)=32a2abb2=6a2+1b1+2=6a3b3(-3a^2b) * (2ab^2) = -3 * 2 * a^2 * a * b * b^2 = -6a^{2+1}b^{1+2} = -6a^3b^3
Second, distribute 3a2b-3a^2b to 2b-2b:
(3a2b)(2b)=32a2bb=6a2b1+1=6a2b2(-3a^2b) * (-2b) = -3 * -2 * a^2 * b * b = 6a^2b^{1+1} = 6a^2b^2
Combining the two terms, we get:
6a3b3+6a2b2-6a^3b^3 + 6a^2b^2

3. Final Answer

6a3b3+6a2b2-6a^3b^3 + 6a^2b^2

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