We are given three functions: $f(x) = \frac{1}{x}$, $r(x) = x+4$, and $m(x) = 8x$. We need to find the composite function $m(f(r(x)))$. Then we have to describe how this composition transforms the parent function $f(x) = \frac{1}{x}$.

AlgebraFunctionsComposite FunctionsTransformationsVertical StretchHorizontal Shift
2025/6/12

1. Problem Description

We are given three functions: f(x)=1xf(x) = \frac{1}{x}, r(x)=x+4r(x) = x+4, and m(x)=8xm(x) = 8x. We need to find the composite function m(f(r(x)))m(f(r(x))). Then we have to describe how this composition transforms the parent function f(x)=1xf(x) = \frac{1}{x}.

2. Solution Steps

First, let's find f(r(x))f(r(x)). Since r(x)=x+4r(x) = x+4 and f(x)=1xf(x) = \frac{1}{x}, we have:
f(r(x))=f(x+4)=1x+4f(r(x)) = f(x+4) = \frac{1}{x+4}
Next, we need to find m(f(r(x)))m(f(r(x))). Since m(x)=8xm(x) = 8x and f(r(x))=1x+4f(r(x)) = \frac{1}{x+4}, we have:
m(f(r(x)))=m(1x+4)=8(1x+4)=8x+4m(f(r(x))) = m(\frac{1}{x+4}) = 8(\frac{1}{x+4}) = \frac{8}{x+4}
Now, let's analyze the transformations of f(x)=1xf(x) = \frac{1}{x} to obtain m(f(r(x)))=8x+4m(f(r(x))) = \frac{8}{x+4}.
* Reflection: There is no reflection across the x-axis or y-axis since there is no negative sign in front of the function or inside the function.
* Stretch/Compression: The function 1x\frac{1}{x} is multiplied by 8, which represents a vertical stretch by a factor of

8. * Vertical Shift: There is no vertical shift since there is no constant added or subtracted outside the fraction.

* Horizontal Shift: The term x+4x+4 inside the function represents a horizontal shift. Since it's x+4x+4, the graph shifts 4 units to the left.

3. Final Answer

1) m(f(r(x)))=8x+4m(f(r(x))) = \frac{8}{x+4}
2)
Reflection: None
Stretch/Compression: Vertical Stretch
Vertical Shift: None
Horizontal Shift: Left

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