Simplify the expression $(8y^3x^{27}x^3)^{\frac{1}{3}}$.

AlgebraExponentsSimplificationAlgebraic ExpressionsRadicals
2025/7/30

1. Problem Description

Simplify the expression (8y3x27x3)13(8y^3x^{27}x^3)^{\frac{1}{3}}.

2. Solution Steps

First, we simplify the expression inside the parentheses by combining the xx terms:
x27x3=x27+3=x30x^{27}x^3 = x^{27+3} = x^{30}.
So the expression becomes (8y3x30)13(8y^3x^{30})^{\frac{1}{3}}.
Next, we apply the exponent 13\frac{1}{3} to each term in the parentheses:
(ab)n=anbn(ab)^n = a^n b^n
(8y3x30)13=813(y3)13(x30)13(8y^3x^{30})^{\frac{1}{3}} = 8^{\frac{1}{3}} (y^3)^{\frac{1}{3}} (x^{30})^{\frac{1}{3}}.
We know that 813=(23)13=2313=21=28^{\frac{1}{3}} = (2^3)^{\frac{1}{3}} = 2^{3*\frac{1}{3}} = 2^1 = 2.
Using the rule (am)n=amn(a^m)^n = a^{m*n}, we have:
(y3)13=y313=y1=y(y^3)^{\frac{1}{3}} = y^{3*\frac{1}{3}} = y^1 = y.
(x30)13=x3013=x10(x^{30})^{\frac{1}{3}} = x^{30*\frac{1}{3}} = x^{10}.
Therefore, (8y3x30)13=2yx10(8y^3x^{30})^{\frac{1}{3}} = 2yx^{10}.

3. Final Answer

2yx102yx^{10}

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