The problem asks to determine the time shown on an analog clock. The hour hand is between 6 and 7, and the minute hand is pointing at 4.

ArithmeticTimeClockMultiplication
2025/3/6

1. Problem Description

The problem asks to determine the time shown on an analog clock. The hour hand is between 6 and 7, and the minute hand is pointing at
4.

2. Solution Steps

* The hour hand is between 6 and 7, meaning it is past 6 o'clock.
* The minute hand is pointing at

4. Each number on the clock represents 5 minutes.

* So, the minutes past the hour are 4×5=204 \times 5 = 20 minutes.
* Therefore, the time is 6:
2
0.

3. Final Answer

6:20

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