We are given a diagram with parallel lines and a triangle. We are asked to find the relationship between the angles $x$, $y$, and $z$.

GeometryParallel LinesTrianglesAngle RelationshipsEuclidean Geometry
2025/7/16

1. Problem Description

We are given a diagram with parallel lines and a triangle. We are asked to find the relationship between the angles xx, yy, and zz.

2. Solution Steps

Let's denote the line segment by their endpoints. Line segment PQPQ is parallel to line segment RSRS. Let the angle at vertex QQ be xx, the angle at vertex RR be yy, and the angle at vertex ZZ be zz.
Since PQPQ is parallel to RSRS, the angle between QRQR and RSRS is equal to the angle between PQPQ and QRQR. This angle is the alternate interior angle and is xx.
In triangle QRZQRZ, the sum of angles in a triangle is 180180^{\circ}.
Therefore, x+y+z=180x+y+z = 180^{\circ}.

3. Final Answer

x+y+z=180x+y+z = 180^{\circ}

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