We are asked to find the value of $y$ in the figure. The polygon has angles $4y$, $4y$, $5y$, $2y$, and $3y$.

1. Problem Description

We are asked to find the value of $y$ in the figure. The polygon has angles $4y$, $4y$, $5y$, $2y$, and $3y$.

2. Solution Steps

The sum of interior angles of a polygon with $n$ sides is given by $(n-2) \times 180^{\circ}$.

In this case, the polygon has 5 sides, so the sum of the interior angles is $(5-2) \times 180^{\circ} = 3 \times 180^{\circ} = 540^{\circ}$.

Therefore, $4y + 4y + 5y + 2y + 3y = 540^{\circ}$.

Combining the terms, we get $18y = 540^{\circ}$.

Dividing both sides by 18, we get $y = \frac{540^{\circ}}{18} = 30^{\circ}$.

3. Final Answer

E. 30°