Car A stops in 24 m. Car B stops in 75% of the distance of car A. We need to find the stopping distance of car B in meters.

1. Problem Description

Car A stops in 24 m. Car B stops in 75% of the distance of car A. We need to find the stopping distance of car B in meters.

2. Solution Steps

First, we need to express 75% as a decimal.

$75\% = \frac{75}{100} = 0.75$

Now, we need to find 75% of the distance car A stopped in, which is 24 m. To do this, we multiply 0.75 by

2

4.

$Distance_{B} = 0.75 \times Distance_{A}$

$Distance_{B} = 0.75 \times 24$

$Distance_{B} = 18$

3. Final Answer

The stopping distance of car B is 18 meters.