The problem asks to simplify the expression $\frac{x+1}{y} \div \frac{2(x+1)}{x}$.

AlgebraAlgebraic simplificationFractionsVariable expressions
2025/7/21

1. Problem Description

The problem asks to simplify the expression x+1y÷2(x+1)x\frac{x+1}{y} \div \frac{2(x+1)}{x}.

2. Solution Steps

To simplify the given expression, we need to remember that dividing by a fraction is the same as multiplying by its reciprocal.
So we can rewrite the expression as:
x+1y÷2(x+1)x=x+1y×x2(x+1)\frac{x+1}{y} \div \frac{2(x+1)}{x} = \frac{x+1}{y} \times \frac{x}{2(x+1)}
Now we can multiply the fractions:
x+1y×x2(x+1)=(x+1)x2y(x+1)\frac{x+1}{y} \times \frac{x}{2(x+1)} = \frac{(x+1)x}{2y(x+1)}
We can cancel the common factor (x+1)(x+1) from the numerator and denominator:
(x+1)x2y(x+1)=x2y\frac{(x+1)x}{2y(x+1)} = \frac{x}{2y}

3. Final Answer

The simplified expression is x2y\frac{x}{2y}.