The problem is to find the length of $HJ$ and the measure of angle $GJN$ given certain information about triangle $GHJ$. We are given that $HP = 5x - 16$, $PJ = 3x + 8$, $m\angle GJN = 6y - 3$, $m\angle NJH = 4y + 23$, and $m\angle HMG = 4z + 14$. Also, we know that $GP$ is a median and an angle bisector.

GeometryTrianglesMediansAngle BisectorsAngle MeasurementSegment Length
2025/7/21

1. Problem Description

The problem is to find the length of HJHJ and the measure of angle GJNGJN given certain information about triangle GHJGHJ. We are given that HP=5x16HP = 5x - 16, PJ=3x+8PJ = 3x + 8, mGJN=6y3m\angle GJN = 6y - 3, mNJH=4y+23m\angle NJH = 4y + 23, and mHMG=4z+14m\angle HMG = 4z + 14. Also, we know that GPGP is a median and an angle bisector.

2. Solution Steps

Since GPGP is a median, PP is the midpoint of HJHJ. Therefore, HP=PJHP = PJ.
5x16=3x+85x - 16 = 3x + 8
2x=242x = 24
x=12x = 12
HP=5(12)16=6016=44HP = 5(12) - 16 = 60 - 16 = 44
PJ=3(12)+8=36+8=44PJ = 3(12) + 8 = 36 + 8 = 44
HJ=HP+PJ=44+44=88HJ = HP + PJ = 44 + 44 = 88
Since GPGP is an angle bisector, mGJN=mNJHm\angle GJN = m\angle NJH.
6y3=4y+236y - 3 = 4y + 23
2y=262y = 26
y=13y = 13
mGJN=6(13)3=783=75m\angle GJN = 6(13) - 3 = 78 - 3 = 75
mNJH=4(13)+23=52+23=75m\angle NJH = 4(13) + 23 = 52 + 23 = 75

3. Final Answer

HJ=88HJ = 88
mGJN=75m\angle GJN = 75

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