We are asked to simplify the expression $3b \cdot (2b^2)^3$.

AlgebraExponentsSimplificationAlgebraic Expressions
2025/4/3

1. Problem Description

We are asked to simplify the expression 3b(2b2)33b \cdot (2b^2)^3.

2. Solution Steps

First, we simplify the term (2b2)3(2b^2)^3 using the power of a product rule, which states that (ab)n=anbn(ab)^n = a^n b^n.
(2b2)3=23(b2)3(2b^2)^3 = 2^3 (b^2)^3
23=222=82^3 = 2 \cdot 2 \cdot 2 = 8.
Next, we use the power of a power rule, which states that (am)n=amn(a^m)^n = a^{m \cdot n}.
(b2)3=b23=b6(b^2)^3 = b^{2 \cdot 3} = b^6.
So, (2b2)3=8b6(2b^2)^3 = 8b^6.
Now, substitute this back into the original expression:
3b(2b2)3=3b8b63b \cdot (2b^2)^3 = 3b \cdot 8b^6.
Multiply the coefficients and add the exponents of bb:
3b8b6=(38)(b1b6)=24b1+6=24b73b \cdot 8b^6 = (3 \cdot 8) (b^1 \cdot b^6) = 24b^{1+6} = 24b^7.

3. Final Answer

24b724b^7

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