Elena writes the equation $6x + 2y = 12$. We need to write a new equation that has: a. exactly one solution in common with Elena's equation b. no solutions in common with Elena's equation c. infinitely many solutions in common with Elena's equation

AlgebraLinear EquationsSystems of EquationsSlope-Intercept FormParallel LinesIntersecting LinesCoincident Lines
2025/4/4

1. Problem Description

Elena writes the equation 6x+2y=126x + 2y = 12. We need to write a new equation that has:
a. exactly one solution in common with Elena's equation
b. no solutions in common with Elena's equation
c. infinitely many solutions in common with Elena's equation

2. Solution Steps

a. Exactly one solution in common:
To have exactly one solution in common, the lines must intersect at a single point. This means the lines must have different slopes.
The given equation is 6x+2y=126x + 2y = 12. We can rewrite it in slope-intercept form (y=mx+by = mx + b) as follows:
2y=6x+122y = -6x + 12
y=3x+6y = -3x + 6
The slope of Elena's equation is 3-3. To get exactly one solution, we need a different slope. Let's pick a slope of 00. An example equation would be y=0y=0, which means 0x+1y=00x + 1y = 0. Substituting y=0y=0 into 6x+2y=126x + 2y = 12, we get 6x+2(0)=126x + 2(0) = 12, which gives 6x=126x=12, so x=2x=2. Thus, the solution (2, 0) satisfies both equations.
b. No solutions in common:
To have no solutions in common, the lines must be parallel and distinct. This means they must have the same slope but different y-intercepts.
The original equation is y=3x+6y = -3x + 6. We need to keep the same slope (3-3) but change the y-intercept. Let's change the y-intercept to 77. Then the equation is y=3x+7y = -3x + 7. Multiplying by 22 and rearranging, we get 2y=6x+142y = -6x + 14, so 6x+2y=146x + 2y = 14.
c. Infinitely many solutions in common:
To have infinitely many solutions, the two equations must represent the same line. This means we can multiply Elena's equation by a constant.
Elena's equation is 6x+2y=126x + 2y = 12. If we multiply this equation by, for example, 22, we get 12x+4y=2412x + 4y = 24.

3. Final Answer

a. An equation with exactly one solution in common is y=0y = 0.
b. An equation with no solutions in common is 6x+2y=146x + 2y = 14.
c. An equation with infinitely many solutions in common is 12x+4y=2412x + 4y = 24.