The problem defines a function $P$ that represents the perimeter of a square with side length $x$. The problem asks us to complete a table of values for $P(x)$ given $x$, write an equation for $P(x)$, and sketch a graph of $P(x)$.

GeometryPerimeterSquaresFunctionsLinear FunctionsGraphing
2025/4/4

1. Problem Description

The problem defines a function PP that represents the perimeter of a square with side length xx. The problem asks us to complete a table of values for P(x)P(x) given xx, write an equation for P(x)P(x), and sketch a graph of P(x)P(x).

2. Solution Steps

a. Completing the table:
The perimeter of a square is given by P=4sP = 4s, where ss is the side length. In this case, the side length is xx, so P(x)=4xP(x) = 4x. We need to calculate P(x)P(x) for x=0,1,2,3,4,5,6x = 0, 1, 2, 3, 4, 5, 6.
P(0)=4(0)=0P(0) = 4(0) = 0
P(1)=4(1)=4P(1) = 4(1) = 4
P(2)=4(2)=8P(2) = 4(2) = 8
P(3)=4(3)=12P(3) = 4(3) = 12
P(4)=4(4)=16P(4) = 4(4) = 16
P(5)=4(5)=20P(5) = 4(5) = 20
P(6)=4(6)=24P(6) = 4(6) = 24
b. Writing an equation to represent function PP:
As explained above, the equation for the perimeter of a square with side length xx is P(x)=4xP(x) = 4x.
c. Sketching a graph of function PP:
We can plot the points from the completed table on the provided graph. The points are (0,0),(1,4),(2,8),(3,12),(4,16),(5,20),(6,24)(0, 0), (1, 4), (2, 8), (3, 12), (4, 16), (5, 20), (6, 24). These points lie on a straight line.

3. Final Answer

a. Completed table:
x | 0 | 1 | 2 | 3 | 4 | 5 | 6
---|---|---|---|---|---|---|---
P(x) | 0 | 4 | 8 | 12 | 16 | 20 | 24
b. Equation for function PP:
P(x)=4xP(x) = 4x
c. Graph:
Plot the points (0,0), (1,4), (2,8), (3,12), (4,16), (5,20), (6,24) and draw a line through these points. Since I cannot directly draw a graph, I will describe it. The graph is a straight line passing through the origin with a slope of

4. For every increase of 1 in the x-direction (side length), the perimeter increases by 4 in the y-direction. The line extends from (0,0) to (6,24) in the range shown on the graph.

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