The problem asks us to determine the degree of static indeterminacy of a rigid plane frame. We need to find the number of members, reactions, and joints in the frame.

Applied MathematicsStructural AnalysisStaticsIndeterminacyPlane Frame
2025/7/26

1. Problem Description

The problem asks us to determine the degree of static indeterminacy of a rigid plane frame. We need to find the number of members, reactions, and joints in the frame.

2. Solution Steps

Step 1: Count the number of members (mm).
The frame has 4 columns and 4 horizontal beams in each bay, with 3 bays. So, there are 4×3=124 \times 3 = 12 vertical members and 4×3=124 \times 3 = 12 horizontal members. Hence, m=12+12=24m = 12 + 12 = 24.
Step 2: Count the number of reactions (rr).
There are two fixed supports and one hinged support. Each fixed support provides 3 reactions (vertical, horizontal, and moment), and the hinged support provides 2 reactions (vertical and horizontal).
Therefore, the total number of reactions is r=(2×3)+2=6+2=8r = (2 \times 3) + 2 = 6 + 2 = 8.
Step 3: Count the number of joints (jj).
There are 4 levels with 4 joints each and in total 12 columns and 12 horizontal beams. Hence there are 12 joints.
Step 4: Calculate the degree of static indeterminacy (DsD_s).
For a rigid plane frame, the degree of static indeterminacy is given by:
Ds=3m+r3jD_s = 3m + r - 3j
Substitute the values:
Ds=3(24)+83(12)D_s = 3(24) + 8 - 3(12)
Ds=72+836D_s = 72 + 8 - 36
Ds=8036D_s = 80 - 36
Ds=44D_s = 44

3. Final Answer

The degree of static indeterminacy is 44.

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