The problem presents a Pascal program segment that initializes and manipulates an array `num` of integers. The program then iterates through a loop from 1 to 5, printing the value of the array element `num[count]` in each iteration. The task is to determine the output of the program.

Discrete MathematicsArraysAlgorithmsProgram ExecutionIndex Manipulation
2025/7/27

1. Problem Description

The problem presents a Pascal program segment that initializes and manipulates an array `num` of integers. The program then iterates through a loop from 1 to 5, printing the value of the array element `num[count]` in each iteration. The task is to determine the output of the program.

2. Solution Steps

First, let's trace the execution of the program and determine the values of the array elements:
* `Num[0] := 8;` The element at index 0 is assigned the value

8. * `Num[3] := 20;` The element at index 3 is assigned the value

2

0. * `Num[5] := Num[3] - 5;` The element at index 5 is assigned the value $20 - 5 = 15$.

* `Num[2] := Num[0] + 5;` The element at index 2 is assigned the value 8+5=138 + 5 = 13.
* `Num[1] := Num[0] + Num[3];` The element at index 1 is assigned the value 8+20=288 + 20 = 28.
* `Num[4] := Num[5] * 2;` The element at index 4 is assigned the value 152=3015 * 2 = 30.
Now, the `for` loop iterates from `count := 1` to `count := 5`. In each iteration, the program prints the value of `num[count]`.
* When `count = 1`, the program prints `num[1]`, which is
2

8. * When `count = 2`, the program prints `num[2]`, which is

1

3. * When `count = 3`, the program prints `num[3]`, which is

2

0. * When `count = 4`, the program prints `num[4]`, which is

3

0. * When `count = 5`, the program prints `num[5]`, which is

1
5.

3. Final Answer

The output of the program is:
28
13
20
30
15

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