The problem asks for the area of a trapezoid with given dimensions. The parallel sides (bases) are 5 yd and 17 yd, and the height is 5 yd. The length of one of the non-parallel sides is given as 13 yd, but this is not needed to find the area.

GeometryAreaTrapezoidGeometric Formulas
2025/4/4

1. Problem Description

The problem asks for the area of a trapezoid with given dimensions. The parallel sides (bases) are 5 yd and 17 yd, and the height is 5 yd. The length of one of the non-parallel sides is given as 13 yd, but this is not needed to find the area.

2. Solution Steps

The area of a trapezoid is given by the formula:
Area=12(b1+b2)hArea = \frac{1}{2} (b_1 + b_2)h
where b1b_1 and b2b_2 are the lengths of the parallel sides (bases) and hh is the height.
In this case, b1=5b_1 = 5 yd, b2=17b_2 = 17 yd, and h=5h = 5 yd.
Plugging in the values:
Area=12(5+17)×5Area = \frac{1}{2} (5 + 17) \times 5
Area=12(22)×5Area = \frac{1}{2} (22) \times 5
Area=11×5Area = 11 \times 5
Area=55Area = 55

3. Final Answer

The area of the trapezoid is 55 yd2yd^2.

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