A kite has one diagonal measuring 33 inches. The area of the kite is 69 square inches. We need to find the length of the other diagonal, rounded to the nearest tenth of an inch.

1. Problem Description

A kite has one diagonal measuring 33 inches. The area of the kite is 69 square inches. We need to find the length of the other diagonal, rounded to the nearest tenth of an inch.

2. Solution Steps

The formula for the area of a kite is:

$Area = \frac{1}{2} * d_1 * d_2$

where $d_1$ and $d_2$ are the lengths of the diagonals.

We are given that the area of the kite is 69 $in^2$ and one diagonal, $d_1$, is 33 inches. Let the other diagonal be $x$. So we have:

$69 = \frac{1}{2} * 33 * x$

Now, we solve for $x$:

$69 = 16.5 * x$

$x = \frac{69}{16.5}$

$x = 4.181818...$

Rounding to the nearest tenth, we get:

$x \approx 4.2$

3. Final Answer

The length of the other diagonal is 4.2 in.