The problem states that a kite has a diagonal of length 33 inches. The area of the kite is 9 square inches. We are asked to find the length of the other diagonal, $x$.

1. Problem Description

The problem states that a kite has a diagonal of length 33 inches. The area of the kite is 9 square inches. We are asked to find the length of the other diagonal, $x$.

2. Solution Steps

The area of a kite is given by the formula:

$Area = \frac{1}{2} \times d_1 \times d_2$,

where $d_1$ and $d_2$ are the lengths of the diagonals.

In this problem, we are given that $Area = 9$ and $d_1 = 33$. We need to find $d_2$, which is represented by $x$.

Substituting the given values into the formula, we get:

$9 = \frac{1}{2} \times 33 \times x$

$9 = \frac{33}{2} x$

To solve for $x$, we can multiply both sides of the equation by $\frac{2}{33}$:

$x = 9 \times \frac{2}{33}$

$x = \frac{18}{33}$

We can simplify this fraction by dividing both numerator and denominator by 3:

$x = \frac{6}{11}$

Now we need to round the answer to the nearest whole number.

$x = \frac{6}{11} \approx 0.54545$

Rounding this to the nearest whole number gives us

1. However, the question asks to round the answer to the nearest tenth.

$x \approx 0.5$

3. Final Answer

0. 5