与えられた正の数・負の数の計算問題を解く。具体的には、足し算、引き算、掛け算、割り算が混ざった13個の計算問題を解く。

算数四則演算負の数分数計算
2025/8/1

1. 問題の内容

与えられた正の数・負の数の計算問題を解く。具体的には、足し算、引き算、掛け算、割り算が混ざった13個の計算問題を解く。

2. 解き方の手順

(1) 19+47=6619 + 47 = 66
(2) 13+(29)=1329=42-13 + (-29) = -13 - 29 = -42
(3) 7.2(1.5)=7.2+1.5=5.7-7.2 - (-1.5) = -7.2 + 1.5 = -5.7
(4) 73+(49)=7349=21949=179\frac{7}{3} + (-\frac{4}{9}) = \frac{7}{3} - \frac{4}{9} = \frac{21}{9} - \frac{4}{9} = \frac{17}{9}
(5) (12)(135)=12+135=510+2610=2110(-\frac{1}{2}) - (-\frac{13}{5}) = -\frac{1}{2} + \frac{13}{5} = -\frac{5}{10} + \frac{26}{10} = \frac{21}{10}
(6) 13(54)(+2)=13+542=412=39-13 - (-54) - (+2) = -13 + 54 - 2 = 41 - 2 = 39
(7) (16)×3=48(-16) \times 3 = -48
(8) (2.6)×(0.5)=1.3(-2.6) \times (-0.5) = 1.3
(9) (37)÷(1249)=(37)×(4912)=3×497×12=3×712=2112=74(-\frac{3}{7}) \div (-\frac{12}{49}) = (-\frac{3}{7}) \times (-\frac{49}{12}) = \frac{3 \times 49}{7 \times 12} = \frac{3 \times 7}{12} = \frac{21}{12} = \frac{7}{4}
(10) (5)×72÷(6)=(5)×(12)=60(-5) \times 72 \div (-6) = (-5) \times (-12) = 60
(11) (52)÷4+(11)×(3)=13+33=20(-52) \div 4 + (-11) \times (-3) = -13 + 33 = 20
(12) (16)×3727×(4)2=(16)×3727×16=592432=1024(-16) \times 37 - 27 \times (-4)^2 = (-16) \times 37 - 27 \times 16 = -592 - 432 = -1024
(13) 60×(16815)92=60×(5301630)92=60×(1130)92=2292=44292=53260 \times (\frac{1}{6} - \frac{8}{15}) - \frac{9}{2} = 60 \times (\frac{5}{30} - \frac{16}{30}) - \frac{9}{2} = 60 \times (-\frac{11}{30}) - \frac{9}{2} = -22 - \frac{9}{2} = -\frac{44}{2} - \frac{9}{2} = -\frac{53}{2}

3. 最終的な答え

(1) 66
(2) -42
(3) -5.7
(4) 179\frac{17}{9}
(5) 2110\frac{21}{10}
(6) 39
(7) -48
(8) 1.3
(9) 74\frac{7}{4}
(10) 60
(11) 20
(12) -1024
(13) 532-\frac{53}{2}