We are asked to factor three quadratic expressions: 1. $2x^2 + 7x + 3$

AlgebraQuadratic EquationsFactorizationAlgebraic Manipulation
2025/8/6

1. Problem Description

We are asked to factor three quadratic expressions:

1. $2x^2 + 7x + 3$

2. $3x^2 + 8x + 4$

3. $2x^2 - x - 15$

2. Solution Steps

1. Factor $2x^2 + 7x + 3$:

We look for two numbers that multiply to 23=62 \cdot 3 = 6 and add to 77. The numbers are 66 and 11.
Rewrite the middle term: 2x2+6x+1x+32x^2 + 6x + 1x + 3.
Factor by grouping: 2x(x+3)+1(x+3)2x(x + 3) + 1(x + 3).
Factor out the common term (x+3)(x + 3): (2x+1)(x+3)(2x + 1)(x + 3).

2. Factor $3x^2 + 8x + 4$:

We look for two numbers that multiply to 34=123 \cdot 4 = 12 and add to 88. The numbers are 66 and 22.
Rewrite the middle term: 3x2+6x+2x+43x^2 + 6x + 2x + 4.
Factor by grouping: 3x(x+2)+2(x+2)3x(x + 2) + 2(x + 2).
Factor out the common term (x+2)(x + 2): (3x+2)(x+2)(3x + 2)(x + 2).

3. Factor $2x^2 - x - 15$:

We look for two numbers that multiply to 215=302 \cdot -15 = -30 and add to 1-1. The numbers are 6-6 and 55.
Rewrite the middle term: 2x26x+5x152x^2 - 6x + 5x - 15.
Factor by grouping: 2x(x3)+5(x3)2x(x - 3) + 5(x - 3).
Factor out the common term (x3)(x - 3): (2x+5)(x3)(2x + 5)(x - 3).

3. Final Answer

1. $2x^2 + 7x + 3 = (2x + 1)(x + 3)$

2. $3x^2 + 8x + 4 = (3x + 2)(x + 2)$

3. $2x^2 - x - 15 = (2x + 5)(x - 3)$

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