The problem is to evaluate the expression $\sqrt{24} + \sqrt{96} - \sqrt{150}$.

1. Problem Description

The problem is to evaluate the expression $\sqrt{24} + \sqrt{96} - \sqrt{150}$.

2. Solution Steps

First, simplify each square root.

$\sqrt{24} = \sqrt{4 \cdot 6} = \sqrt{4} \cdot \sqrt{6} = 2\sqrt{6}$

$\sqrt{96} = \sqrt{16 \cdot 6} = \sqrt{16} \cdot \sqrt{6} = 4\sqrt{6}$

$\sqrt{150} = \sqrt{25 \cdot 6} = \sqrt{25} \cdot \sqrt{6} = 5\sqrt{6}$

Now substitute the simplified radicals into the original expression.

$2\sqrt{6} + 4\sqrt{6} - 5\sqrt{6} = (2 + 4 - 5)\sqrt{6} = (6 - 5)\sqrt{6} = 1\sqrt{6} = \sqrt{6}$

3. Final Answer

$\sqrt{6}$