We are asked to find the value of $x$ in the given figure. The figure shows two right triangles sharing a common side. We need to express the answer in the simplest radical form.

GeometryPythagorean TheoremRight TrianglesRadicalsTriangle Geometry
2025/3/12

1. Problem Description

We are asked to find the value of xx in the given figure. The figure shows two right triangles sharing a common side. We need to express the answer in the simplest radical form.

2. Solution Steps

Let the length of the common side be yy.
For the smaller right triangle, using the Pythagorean theorem, we have
42+62=y24^2 + 6^2 = y^2
16+36=y216 + 36 = y^2
y2=52y^2 = 52
For the larger right triangle, using the Pythagorean theorem, we have
x2+y2=92x^2 + y^2 = 9^2
x2+52=81x^2 + 52 = 81
x2=8152x^2 = 81 - 52
x2=29x^2 = 29
x=29x = \sqrt{29}

3. Final Answer

x=29x = \sqrt{29}

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