We are given a right triangle with legs of length $a$ and $b$, and a hypotenuse of length $c$. We are given $a = 4$ meters and $c = 8$ meters. We need to find the length of side $b$, rounded to the nearest tenth.

1. Problem Description

We are given a right triangle with legs of length $a$ and $b$, and a hypotenuse of length $c$. We are given $a = 4$ meters and $c = 8$ meters. We need to find the length of side $b$, rounded to the nearest tenth.

2. Solution Steps

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

$a^2 + b^2 = c^2$

We are given $a = 4$ and $c = 8$, so we can substitute these values into the equation:

$4^2 + b^2 = 8^2$

$16 + b^2 = 64$

$b^2 = 64 - 16$

$b^2 = 48$

$b = \sqrt{48}$

$b \approx 6.928$

Rounding to the nearest tenth, $b \approx 6.9$.

3. Final Answer

6.9 meters