The problem provides two vectors, $u$ and $v$, defined as $u = -i + 3j + k$ and $v = 4i + 7j$. This implies $u = <-1, 3, 1>$ and $v = <4, 7, 0>$.

Applied MathematicsVectorsDot ProductLinear Algebra3D Vectors
2025/3/12

1. Problem Description

The problem provides two vectors, uu and vv, defined as u=i+3j+ku = -i + 3j + k and v=4i+7jv = 4i + 7j. This implies u=<1,3,1>u = <-1, 3, 1> and v=<4,7,0>v = <4, 7, 0>.

2. Solution Steps

Since the problem doesn't specify what to compute, let us compute the dot product of u and v (uvu \cdot v).
The dot product of two vectors u=<u1,u2,u3>u = <u_1, u_2, u_3> and v=<v1,v2,v3>v = <v_1, v_2, v_3> is given by:
uv=u1v1+u2v2+u3v3u \cdot v = u_1v_1 + u_2v_2 + u_3v_3
In our case, u=<1,3,1>u = <-1, 3, 1> and v=<4,7,0>v = <4, 7, 0>. Thus,
uv=(1)(4)+(3)(7)+(1)(0)u \cdot v = (-1)(4) + (3)(7) + (1)(0)
uv=4+21+0u \cdot v = -4 + 21 + 0
uv=17u \cdot v = 17

3. Final Answer

The dot product uv=17u \cdot v = 17.

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