The problem provides the pressure exerted by a brick on a table ($240 \ N/m^2$) and the area of the base of the brick ($0.03 \ m^2$). We are asked to calculate the force, in Newtons (N), that the brick exerts on the table.

Applied MathematicsPhysicsPressureForceAreaUnits Conversion
2025/6/5

1. Problem Description

The problem provides the pressure exerted by a brick on a table (240 N/m2240 \ N/m^2) and the area of the base of the brick (0.03 m20.03 \ m^2). We are asked to calculate the force, in Newtons (N), that the brick exerts on the table.

2. Solution Steps

The formula relating pressure, force, and area is given by:
pressure=forceareapressure = \frac{force}{area}
We are given the pressure and the area, and we need to find the force. We can rearrange the formula to solve for force:
force=pressure×areaforce = pressure \times area
Now, we can plug in the given values:
force=240 N/m2×0.03 m2force = 240 \ N/m^2 \times 0.03 \ m^2
force=7.2 Nforce = 7.2 \ N

3. Final Answer

The force that the brick exerts on the table is 7.2 N7.2 \ N.

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