The problem provides an equation to calculate the accrued value $A$ of an investment made by Jolene: $A = 18600(1.071)^t$, where $t$ is the length of the investment in years. We are asked to: a) Determine the amount of money Jolene will have after 16 years, rounded to two decimal places. b) Determine how long it will take for Jolene to have $118,530.10 accrued, rounded to the nearest whole year.

Applied MathematicsCompound InterestExponential GrowthFinancial MathematicsLogarithms
2025/4/7

1. Problem Description

The problem provides an equation to calculate the accrued value AA of an investment made by Jolene: A=18600(1.071)tA = 18600(1.071)^t, where tt is the length of the investment in years.
We are asked to:
a) Determine the amount of money Jolene will have after 16 years, rounded to two decimal places.
b) Determine how long it will take for Jolene to have $118,530.10 accrued, rounded to the nearest whole year.

2. Solution Steps

a) To find the amount of money Jolene will have after 16 years, we substitute t=16t = 16 into the equation:
A=18600(1.071)16A = 18600(1.071)^{16}
A=18600(3.02276)A = 18600(3.02276)
A=56223.336A = 56223.336
Rounding to two decimal places, we get A=56223.34A = 56223.34.
b) To find how long it will take for Jolene to have 118,530.10accrued,weset118,530.10 accrued, we set A = 118530.10andsolvefor and solve for t$:
118530.10=18600(1.071)t118530.10 = 18600(1.071)^t
Divide both sides by 18600:
118530.1018600=(1.071)t\frac{118530.10}{18600} = (1.071)^t
6.372586=(1.071)t6.372586 = (1.071)^t
Take the natural logarithm of both sides:
ln(6.372586)=ln((1.071)t)ln(6.372586) = ln((1.071)^t)
ln(6.372586)=tln(1.071)ln(6.372586) = t * ln(1.071)
t=ln(6.372586)ln(1.071)t = \frac{ln(6.372586)}{ln(1.071)}
t=1.85240.0685t = \frac{1.8524}{0.0685}
t=27.03t = 27.03
Rounding to the nearest whole year, we get t=27t = 27.

3. Final Answer

Answer: After 16 years, Jolene will have $56223.34 in her savings account. (Round to TWO decimal places.)
Answer: Jolene will have accrued $118,530.10 in her savings after 27 years. (Round to the nearest whole year.)

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