Dalton plans to roll a fair 6-sided die 300 times. We need to find the best prediction for the number of times he will roll a 5 or a 6.

Probability and StatisticsProbabilityExpected ValueDiscrete ProbabilityDie Roll
2025/3/12

1. Problem Description

Dalton plans to roll a fair 6-sided die 300 times. We need to find the best prediction for the number of times he will roll a 5 or a
6.

2. Solution Steps

A fair 6-sided die has 6 possible outcomes: 1, 2, 3, 4, 5, and

6. The probability of rolling a 5 is $\frac{1}{6}$.

The probability of rolling a 6 is 16\frac{1}{6}.
The probability of rolling a 5 or a 6 is the sum of the individual probabilities:
P(5 or 6)=P(5)+P(6)=16+16=26=13P(5 \text{ or } 6) = P(5) + P(6) = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}.
The expected number of times he will roll a 5 or a 6 in 300 rolls is the probability of rolling a 5 or 6 multiplied by the number of rolls:
E=(number of rolls)×P(5 or 6)=300×13=100E = (\text{number of rolls}) \times P(5 \text{ or } 6) = 300 \times \frac{1}{3} = 100.

3. Final Answer

100

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