The problem asks us to find the distance between the points $(7, 14)$ and $(12, 2)$.

GeometryDistance FormulaCoordinate GeometryEuclidean Distance
2025/3/12

1. Problem Description

The problem asks us to find the distance between the points (7,14)(7, 14) and (12,2)(12, 2).

2. Solution Steps

We can use the distance formula to find the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in a coordinate plane.
The distance formula is:
d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
In this case, (x1,y1)=(7,14)(x_1, y_1) = (7, 14) and (x2,y2)=(12,2)(x_2, y_2) = (12, 2).
Plugging in the values, we get:
d=(127)2+(214)2d = \sqrt{(12 - 7)^2 + (2 - 14)^2}
d=(5)2+(12)2d = \sqrt{(5)^2 + (-12)^2}
d=25+144d = \sqrt{25 + 144}
d=169d = \sqrt{169}
d=13d = 13

3. Final Answer

The distance between the points (7, 14) and (12, 2) is 13 units.

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