The problem requires us to determine whether the given functions are linear or nonlinear. The functions are: $y = \frac{1}{2}x + 1$ $y = 3x - 1$ $y = \frac{1}{x} - 2$ $y = 2$

AlgebraLinear FunctionsNonlinear FunctionsFunction AnalysisSlope-intercept form
2025/3/12

1. Problem Description

The problem requires us to determine whether the given functions are linear or nonlinear. The functions are:
y=12x+1y = \frac{1}{2}x + 1
y=3x1y = 3x - 1
y=1x2y = \frac{1}{x} - 2
y=2y = 2

2. Solution Steps

A linear function has the general form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. Any function that cannot be written in this form is nonlinear.
* Function 1: y=12x+1y = \frac{1}{2}x + 1
This function is in the form y=mx+by = mx + b, where m=12m = \frac{1}{2} and b=1b = 1. Thus, it is a linear function.
* Function 2: y=3x1y = 3x - 1
This function is in the form y=mx+by = mx + b, where m=3m = 3 and b=1b = -1. Thus, it is a linear function.
* Function 3: y=1x2y = \frac{1}{x} - 2
This function can be rewritten as y=x12y = x^{-1} - 2. Since the exponent of xx is -1, this function is not linear. It is a nonlinear function.
* Function 4: y=2y = 2
This function can be written as y=0x+2y = 0x + 2, which is in the form y=mx+by = mx + b, where m=0m = 0 and b=2b = 2. Thus, it is a linear function.

3. Final Answer

y=12x+1y = \frac{1}{2}x + 1: Linear
y=3x1y = 3x - 1: Linear
y=1x2y = \frac{1}{x} - 2: Nonlinear
y=2y = 2: Linear

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