We are given the function $f(x) = 2x^3 + qx + 2$, where $q$ is a constant. We are also given that $f(-1) = 2$. We need to find the value of $q$.

AlgebraPolynomialsFunction EvaluationSolving Equations
2025/4/8

1. Problem Description

We are given the function f(x)=2x3+qx+2f(x) = 2x^3 + qx + 2, where qq is a constant. We are also given that f(1)=2f(-1) = 2. We need to find the value of qq.

2. Solution Steps

We substitute x=1x = -1 into the expression for f(x)f(x):
f(1)=2(1)3+q(1)+2f(-1) = 2(-1)^3 + q(-1) + 2
Since we know that f(1)=2f(-1) = 2, we can write:
2=2(1)3+q(1)+22 = 2(-1)^3 + q(-1) + 2
2=2(1)q+22 = 2(-1) - q + 2
2=2q+22 = -2 - q + 2
2=q2 = -q
Multiply both sides by -1:
2=q-2 = q
Therefore, q=2q = -2.

3. Final Answer

q=2q = -2

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