The problem is to solve the following system of equations: $x + y = 4$ $z - y = 3$ $2x + 2z = 3$

AlgebraSystem of EquationsLinear EquationsSolution ExistenceContradiction
2025/4/20

1. Problem Description

The problem is to solve the following system of equations:
x+y=4x + y = 4
zy=3z - y = 3
2x+2z=32x + 2z = 3

2. Solution Steps

From the first equation, we have:
x=4yx = 4 - y (1)
From the second equation, we have:
z=y+3z = y + 3 (2)
Substitute equations (1) and (2) into the third equation:
2(4y)+2(y+3)=32(4 - y) + 2(y + 3) = 3
82y+2y+6=38 - 2y + 2y + 6 = 3
14=314 = 3
This is a contradiction, meaning the system of equations has no solution.

3. Final Answer

No solution.

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