The image describes the Law of Total Probability. Given a sample space $S$ of an experiment $E$, and an event $A$ in $E$. Suppose $B_1, B_2, ..., B_n$ form a partition of $S$, with $P(B_i) > 0$ for $i=1, 2, ..., n$. The problem presents the formula for the probability of event $A$, $P(A)$.

Probability and StatisticsProbabilityLaw of Total ProbabilityConditional ProbabilityEventsSample SpacePartition
2025/4/9

1. Problem Description

The image describes the Law of Total Probability. Given a sample space SS of an experiment EE, and an event AA in EE. Suppose B1,B2,...,BnB_1, B_2, ..., B_n form a partition of SS, with P(Bi)>0P(B_i) > 0 for i=1,2,...,ni=1, 2, ..., n. The problem presents the formula for the probability of event AA, P(A)P(A).

2. Solution Steps

The Law of Total Probability states that if events B1,B2,...,BnB_1, B_2, ..., B_n form a partition of the sample space SS, then the probability of any event AA can be expressed as the sum of the probabilities of AA occurring with each of the BiB_i events. This can be represented as:
P(A)=P(AB1)+P(AB2)+...+P(ABn)P(A) = P(A \cap B_1) + P(A \cap B_2) + ... + P(A \cap B_n).
Since P(ABi)=P(ABi)P(Bi)P(A \cap B_i) = P(A|B_i)P(B_i), the Law of Total Probability can be written as:
P(A)=P(AB1)P(B1)+P(AB2)P(B2)+...+P(ABn)P(Bn)P(A) = P(A|B_1)P(B_1) + P(A|B_2)P(B_2) + ... + P(A|B_n)P(B_n).

3. Final Answer

P(A)=P(AB1)P(B1)+P(AB2)P(B2)+...+P(ABn)P(Bn)P(A) = P(A|B_1)P(B_1) + P(A|B_2)P(B_2) + ... + P(A|B_n)P(B_n)

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