A tank is initially filled with $\frac{5}{8}$ of its capacity with oil. Due to a leak, $\frac{1}{5}$ of the oil in the tank is wasted during a day. (i) What fraction of the whole tank was empty at the beginning? (ii) What fraction of the oil in the whole tank got wasted during a day? (iii) At the end of the day, if 100 liters of oil was remaining in the tank, what is the capacity of the tank? (iv) If one liter of oil costs Rs. 450, find the value of the oil that got wasted.

ArithmeticFractionsPercentageWord ProblemsRate of Change
2025/4/9

1. Problem Description

A tank is initially filled with 58\frac{5}{8} of its capacity with oil. Due to a leak, 15\frac{1}{5} of the oil in the tank is wasted during a day.
(i) What fraction of the whole tank was empty at the beginning?
(ii) What fraction of the oil in the whole tank got wasted during a day?
(iii) At the end of the day, if 100 liters of oil was remaining in the tank, what is the capacity of the tank?
(iv) If one liter of oil costs Rs. 450, find the value of the oil that got wasted.

2. Solution Steps

(i) Fraction of tank empty at beginning:
Since the tank is 58\frac{5}{8} filled, the empty portion is 1581 - \frac{5}{8}.
158=8858=381 - \frac{5}{8} = \frac{8}{8} - \frac{5}{8} = \frac{3}{8}
(ii) Fraction of oil wasted during the day:
The fraction of oil wasted is 15\frac{1}{5} of the 58\frac{5}{8} of the tank's capacity that was initially filled.
Fraction of oil wasted = 15×58=1×55×8=540=18\frac{1}{5} \times \frac{5}{8} = \frac{1 \times 5}{5 \times 8} = \frac{5}{40} = \frac{1}{8}
(iii) Capacity of the tank:
Let the capacity of the tank be xx liters.
Initially, the tank had 58x\frac{5}{8}x liters of oil.
Oil wasted = 18x\frac{1}{8}x liters
Remaining oil = Initial oil - Wasted oil
100=58x18x=48x=12x100 = \frac{5}{8}x - \frac{1}{8}x = \frac{4}{8}x = \frac{1}{2}x
100=12x100 = \frac{1}{2}x
x=2×100=200x = 2 \times 100 = 200
So, the capacity of the tank is 200 liters.
(iv) Value of the oil that got wasted:
The amount of oil wasted is 18\frac{1}{8} of the tank's capacity, which is 18×200=25\frac{1}{8} \times 200 = 25 liters.
Cost of 1 liter of oil = Rs. 450
Cost of 25 liters of oil = 25×450=1125025 \times 450 = 11250

3. Final Answer

(i) 38\frac{3}{8}
(ii) 18\frac{1}{8}
(iii) 200 liters
(iv) Rs. 11250

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