The problem consists of two sub-problems: (1) If 1 meter of ribbon costs 240 yen, what is the cost of $\frac{3}{4}$ meters of ribbon? (2) If 1 liter of oil weighs $\frac{7}{8}$ kg, what is the weight of $\frac{4}{5}$ liters of oil?

ArithmeticFractionsMultiplicationUnit Conversion
2025/6/9

1. Problem Description

The problem consists of two sub-problems:
(1) If 1 meter of ribbon costs 240 yen, what is the cost of 34\frac{3}{4} meters of ribbon?
(2) If 1 liter of oil weighs 78\frac{7}{8} kg, what is the weight of 45\frac{4}{5} liters of oil?

2. Solution Steps

(1) The cost of 34\frac{3}{4} meters of ribbon can be found by multiplying the cost per meter by the length of the ribbon.
Cost = (Cost per meter) * (Length in meters)
Cost = 240×34240 \times \frac{3}{4}
240×34=240×34=7204=180240 \times \frac{3}{4} = \frac{240 \times 3}{4} = \frac{720}{4} = 180
The cost of 34\frac{3}{4} meters of ribbon is 180 yen.
(2) The weight of 45\frac{4}{5} liters of oil can be found by multiplying the weight per liter by the volume of the oil.
Weight = (Weight per liter) * (Volume in liters)
Weight = 78×45\frac{7}{8} \times \frac{4}{5}
78×45=7×48×5=2840=710\frac{7}{8} \times \frac{4}{5} = \frac{7 \times 4}{8 \times 5} = \frac{28}{40} = \frac{7}{10}
The weight of 45\frac{4}{5} liters of oil is 710\frac{7}{10} kg.

3. Final Answer

(1) 180
(2) 710\frac{7}{10}

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