The problem states that a vacuum cleaner depreciates in value each month. We are given the values of the vacuum cleaner for the first three months and need to calculate: a) The multiplier used to calculate the value each month. b) The percentage of value lost each month. c) Whether the vacuum cleaner will be worth less than $100 after 1 year (12 months).

Applied MathematicsExponential DecayPercentageDepreciationModeling
2025/4/9

1. Problem Description

The problem states that a vacuum cleaner depreciates in value each month. We are given the values of the vacuum cleaner for the first three months and need to calculate:
a) The multiplier used to calculate the value each month.
b) The percentage of value lost each month.
c) Whether the vacuum cleaner will be worth less than $100 after 1 year (12 months).

2. Solution Steps

a) To find the multiplier, we can divide the value of the vacuum cleaner in one month by its value in the previous month.
Multiplier from month 0 to month 1:
multiplier1=12881400=0.92multiplier_1 = \frac{1288}{1400} = 0.92
Multiplier from month 1 to month 2:
multiplier2=1184.961288=0.92multiplier_2 = \frac{1184.96}{1288} = 0.92
Multiplier from month 2 to month 3:
multiplier3=1090.161184.96=0.92multiplier_3 = \frac{1090.16}{1184.96} = 0.92
Since the multipliers are approximately the same, the multiplier to calculate the value each month is 0.
9
2.
b) To find the percentage of value lost each month, we can subtract the multiplier from 1 and multiply by
1
0

0. $percentage\_lost = (1 - multiplier) * 100$

percentage_lost=(10.92)100=0.08100=8%percentage\_lost = (1 - 0.92) * 100 = 0.08 * 100 = 8\%
The vacuum cleaner loses 8% of its value each month.
c) To determine if the vacuum cleaner will be worth less than $100 after 1 year, we can use the formula for exponential decay:
Value(t)=InitialValue(multiplier)tValue(t) = InitialValue * (multiplier)^t
Where t is the number of months. In this case t=12, InitialValue = $1400 and multiplier = 0.
9
2.
Value(12)=1400(0.92)12Value(12) = 1400 * (0.92)^{12}
Value(12)=14000.36766671=514.7334Value(12) = 1400 * 0.36766671 = 514.7334
Since 514.73>100514.73 > 100, the vacuum cleaner will not be worth less than $100 after 1 year.

3. Final Answer

a) The multiplier to calculate the value each month is 0.
9

2. b) The vacuum cleaner is losing 8% of its value each time.

c) No, in 1 year the vacuum cleaner will not be worth less than $
1
0

0. Its approximate value is $514.

7
3.

Related problems in "Applied Mathematics"

We are given a graph showing the population of trout over time. We need to answer questions related ...

Population ModelingCarrying CapacityGraph InterpretationEcology
2025/4/15

The problem presents a graph showing the changes in the size of a trout (fish) population over time....

Population DynamicsGraph InterpretationCarrying CapacityModeling
2025/4/15

The problem describes a graph representing the growth of a fly population in a jar. The questions as...

Population GrowthCarrying CapacityGraph AnalysisModeling
2025/4/15

We are given a population graph of trout over time. a. We need to identify what the dashed line repr...

Population ModelingCarrying CapacityGraph InterpretationEcology
2025/4/15

We are given three financial problems to solve: (8) A man invests Tk. 10,000 and withdraws Tk. 1,500...

Financial MathematicsCompound InterestAnnuitiesAmortization SchedulePresent ValueFuture Value
2025/4/14

An organic compound containing only C, H, and O is analyzed. 1.491 g of the substance yields 3.540 ...

StoichiometryEmpirical FormulaMolar MassIdeal Gas LawChemical Composition
2025/4/14

The problem describes an organic compound A composed of Carbon (C), Hydrogen (H), and Oxygen (O). 1)...

ChemistryStoichiometryMolar MassEmpirical FormulaGas Laws
2025/4/14

Exercise 12: An organic compound containing only carbon, hydrogen, oxygen, and nitrogen is analyzed....

ChemistryStoichiometryPercentage CompositionMolecular FormulaMolar MassEmpirical Formula
2025/4/14

We are given information about the combustion of an organic compound containing carbon, hydrogen, an...

StoichiometryEmpirical FormulaIdeal Gas LawVapor DensityMolar Mass DeterminationChemistry
2025/4/14

A compound containing carbon, hydrogen, and oxygen is analyzed. 1) 1.491g of the substance yields 3....

ChemistryStoichiometryPercentage CompositionIdeal Gas LawEmpirical FormulaMolar Mass
2025/4/14