The problem asks for the probability of spinning a spinner twice and landing on a number greater than 5 on the first spin and then landing on a number less than 5 on the second spin. The spinner has four sections labeled 3, 4, 5, and 6. We need to express the probability as a percentage.

1. Problem Description

The problem asks for the probability of spinning a spinner twice and landing on a number greater than 5 on the first spin and then landing on a number less than 5 on the second spin. The spinner has four sections labeled 3, 4, 5, and

6. We need to express the probability as a percentage.

2. Solution Steps

First, we need to determine the probability of landing on a number greater than 5 on the first spin. The only number greater than 5 is

6. Since there are 4 equal sections, the probability of landing on 6 is $\frac{1}{4}$.

Next, we need to determine the probability of landing on a number less than 5 on the second spin. The numbers less than 5 are 3 and

4. Since there are 4 equal sections, the probability of landing on 3 or 4 is $\frac{2}{4} = \frac{1}{2}$.

Since the two spins are independent events, we multiply the probabilities together:

$P(\text{greater than 5 then less than 5}) = P(\text{greater than 5}) \times P(\text{less than 5}) = \frac{1}{4} \times \frac{1}{2} = \frac{1}{8}$

To convert this fraction to a percentage, we multiply by 100:

$\frac{1}{8} \times 100 = 12.5$

3. Final Answer

1

2. 5%