The problem asks to find the metal cost per square foot of a cylindrical tank with height 2 ft and diameter 12 ft. The total cost of the metal is $9636.10.

1. Problem Description

The problem asks to find the metal cost per square foot of a cylindrical tank with height 2 ft and diameter 12 ft. The total cost of the metal is $9636.

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2. Solution Steps

First, we need to find the radius of the cylinder.

$radius = diameter / 2$

$radius = 12 ft / 2 = 6 ft$

Next, we need to find the surface area of the cylinder. The formula for the surface area of a cylinder is:

$Surface Area = 2 * \pi * radius * height + 2 * \pi * radius^2$

$Surface Area = 2 * \pi * (6 ft) * (2 ft) + 2 * \pi * (6 ft)^2$

$Surface Area = 2 * \pi * 12 ft^2 + 2 * \pi * 36 ft^2$

$Surface Area = 24\pi ft^2 + 72\pi ft^2$

$Surface Area = 96\pi ft^2$

Using the $\pi$ button on the calculator, we have:

$Surface Area \approx 96 * 3.14159265359 ft^2$

$Surface Area \approx 301.5928947 ft^2$

Now, we can find the cost per square foot by dividing the total cost by the surface area.

$Cost Per Square Foot = Total Cost / Surface Area$

$Cost Per Square Foot =$9636.10 / 301.5928947 ft^2$

$Cost Per Square Foot \approx$

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3. Final Answer

$32.00