We are given a radioactive isotope with a half-life of 5 years. We are given an initial amount of 120 grams. We want to find the equation that determines the amount of material remaining, $y$, after $x$ years.

Applied MathematicsExponential DecayRadioactive DecayHalf-lifeModeling
2025/4/10

1. Problem Description

We are given a radioactive isotope with a half-life of 5 years. We are given an initial amount of 120 grams. We want to find the equation that determines the amount of material remaining, yy, after xx years.

2. Solution Steps

The general formula for exponential decay (including radioactive decay) is
y=A(1/2)t/Ty = A(1/2)^{t/T}
where yy is the amount remaining after time tt, AA is the initial amount, and TT is the half-life.
In this case, we have A=120A=120 grams, T=5T = 5 years, and t=xt = x years. Substituting these values into the formula, we get:
y=120(1/2)x/5y = 120(1/2)^{x/5}
Therefore, the correct equation is y=120×(1/2)x/5y = 120 \times (1/2)^{x/5}.

3. Final Answer

y=120×(12)x5y = 120 \times (\frac{1}{2})^{\frac{x}{5}}

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