A man moves from point $T$ 12 km due West and then 12 km due South to point $Q$. We need to find the bearing of $T$ from $Q$.

1. Problem Description

A man moves from point $T$ 12 km due West and then 12 km due South to point $Q$. We need to find the bearing of $T$ from $Q$.

2. Solution Steps

First, visualize the movements. The man starts at $T$, moves 12 km West, and then 12 km South to reach $Q$. This forms a right-angled triangle where the West and South movements are the legs, and the line connecting $T$ and $Q$ is the hypotenuse. We are looking for the bearing of $T$ from $Q$, which is the angle measured clockwise from the North direction at point $Q$ to the line connecting $Q$ and $T$.

The angle between the South direction at $Q$ and the line $QT$ is $\theta$, where $\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{12}{12} = 1$. Therefore, $\theta = \arctan(1) = 45^{\circ}$.

Since we want the bearing of $T$ from $Q$, we measure clockwise from North at point $Q$. Starting from North, we go $180^{\circ}$ to South, and then add the angle $\theta = 45^{\circ}$.

So, the bearing is $180^{\circ} + 45^{\circ} = 225^{\circ}$.

3. Final Answer

A. 225°