We are given a cone with base radius $r = 8$ cm and height $h = 11$ cm. We need to calculate the curved surface area of the cone, correct to two decimal places, using $\pi = \frac{22}{7}$.

1. Problem Description

We are given a cone with base radius $r = 8$ cm and height $h = 11$ cm. We need to calculate the curved surface area of the cone, correct to two decimal places, using $\pi = \frac{22}{7}$.

2. Solution Steps

First, we need to find the slant height $l$ of the cone. The slant height, height, and radius are related by the Pythagorean theorem:

$l^2 = r^2 + h^2$

$l = \sqrt{r^2 + h^2}$

Substituting the given values, we get

$l = \sqrt{8^2 + 11^2} = \sqrt{64 + 121} = \sqrt{185}$

Now, we can calculate the curved surface area $A$ of the cone using the formula:

$A = \pi r l$

Substituting the values $r = 8$, $l = \sqrt{185}$, and $\pi = \frac{22}{7}$, we get

$A = \frac{22}{7} \times 8 \times \sqrt{185}$

$A = \frac{22}{7} \times 8 \times 13.6014705$

$A = \frac{22}{7} \times 108.811764$

$A = 341.9754$

Rounding to two decimal places, we get $341.98$.

3. Final Answer

The curved surface area of the cone is $341.98 \ cm^2$. The correct option is A.